Physics, asked by suryawanshiaditya315, 2 months ago

When voltage applied to a diode is more than PIV, it is likely to result

a) Conduction in both direction

b) diodes gets destroyed

c) diodes behaves as zener diode

d) More distortion on output side​

Answers

Answered by Anonymous
0

Answer:

Option (C) Diodes behaves as zener diode.

Explanation:

Because it is a Breakdown at the junction.

Answered by mad210215
0

When the voltage applied to a diode is more than PIV :

Explanation:

  • Break down of a diode happens throughout its reverse biased condition. At a point that we can decide as a breakdown point, the diode can get broken. At this time, the diode behaves a lot like a shorted wire, and hence current flows through it simply.
  • The peak inverse voltage rating of a diode is also defined as because the value of the reverse voltage that a PN-junction (or diode) will withstand while not damaging (or destruction). It's the height inverse voltage rating (PIV) of a diode.
  • Zener breakdown occurs because of the rise within the electric field. A high electric field will increase break the covalent bonds that lead to the rise of charge carriers. In Avalanche breakdown, the velocity of the minority carriers is increased by the rise within the electric field.

The correct option is c.

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