Question

when we double the concentration of reactants the rate of reaction becomes double then this reaction is of which order

Answer 1

Answer:

When we double the concentration of reactants, the rate of reaction becomes double only when the reaction follows first-order kinetics·

Explanation:

Given that,

When we double the concentration of reactants the rate of reaction also doubles· So, here the rate of the reaction is directly dependent on the concentration of the reactants·

The rate of a reaction is defined as ''the speed at which a chemical reaction proceeds"· It is usually expressed as the rate law which depends on the concentration of the reactants and its stoichiometric coefficients· The expression for the rate law of a reaction,

    xA  $+$  yB   →   products

    Rate $=$  K $[A]^x\ [B]^y$

where,

A and B are the two reactants·

x and y are their stoichiometric coefficients·

$x\ +\ y$   $=$  The order of a reaction

According to that, there are different types of order of reactions zero-order, first-order, second-order, and mixed-order reations·

The rate law for these types of reactions are,

⇒  For zero-order kinetics, the rate expression follows

     Rate $=$ K

Here,

The order is zero and the rate of the reaction is independent of the concentration of the reactants·

⇒ For first-order kinetics, the rate expression follows

    Rate  $=$ K $[A]$

Here,

The order is one and the rate of the reaction is directly dependent on the concentration of the reactant A·

⇒ For second-order kinetics, the rate expression follows

    Rate  $=$  K $[A]^2$

Here,

The order is two and the rate of the reaction is depending on the concentration of the reactant raised to the power $2.$

⇒  For mixed-order kinetics the rate expression follows

     Rate  $=$  K $[A]^{\frac{m}{n} }$

Here,

The order can be any fractional value and the rate of the reaction is depending on the concentration of the reactant A raised to the fractional value·

Therefore,

From the above information, the rate of the reaction is directly dependent on the concentration of the reactants is in the first-order kinetics·

So, when we double the concentration of reactants the rate of reaction becomes double only when the order of the reaction $=\ 1$

That is, the reaction follows first-order reaction·

Answer 2

Answer:

first order reaction

Explanation:

For a first order reaction, rate =k[A], when concentration of A is doubled, the rate becomes double.