When we multiply a certain two-digit number by the sum of its digits, 405 is achieved. if youmultiply the number written in reverse order of the same digits by the sum of the digits, we get486. find the number?
Answers
Answered by
2
(10a+b)(a+b)=405 and
(10b+a)(a+b)=486
from these two we can conclude that the last digit of the number should be 5. so, by simplifying the first equation, we get 10a^2+55a+25=405.
thats 10a^2+55a=380.
now a should be an even number..so we check for 2 and then for 4.. which satisfies the equation.giving the answer as 45
Similar questions