When (x-1/x)=5, find value of (x^2-1/x^2)
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0
Answer:
17
Step-by-step explanation:
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Answered by
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Answer:
Step-by-step explanation:
=> (x-1/x)=5
=> 5x=x-1 ( by crossing )
=> 5x -x= -1
=> 4x = -1
=> x= -1/4 ( now put the value of x = -1/4 in x^2-1/x^2)
=> (-1/4)^2-1 / (-1/4)^2
=> 1/16 - 1 / 1/16
=> 1-16/ 16 / 1/16
=> - 15/16 / 1/16
=> -15/16 * 16
=> -15 ( 16 to 16 get cancelled)
hope it helps you : )
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