Question

When x molecules are removed from 200 mg of n2o 2.89×10?

Answer 1

Answer:9.969×1020

Explanation:

The molecular weight of N2O is 14×2+16=44.

The number of molecules of a gas in 1 gram mole is the Avagadro’s number 6.022×1023.

⇒ The number of molecules of N2O in 200 mg of gas is

6.022×1023×0.244=2.7373×1021.

The quantity of gas left after removing x molecules is 2.89×10−3 moles.

⇒ The number of molecules left =  2.89×10−3×6.022×1023=1.7404×1021.  

⇒x=2.7373×1021−1.7404×1021=9.969×1020