when (x3-2x2+px-q)is is divided by (x2-2x-3),THE remainder is (x-6).Find the value of p and q.
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Given :- when (x³-2x²+px-q) is is divided by (x²-2x-3), The remainder is (x-6). Find the value of p and q ?
Answer :-
dividing by long division method we get,
x² - 2x - 3 ) x³- 2x²+ px - q (x
x³ - 2x² -3x
(px + 3x) - q
Remainder = (p + 3)x - q
given remainder = (x - 6)
so,
→ (p + 3)x - q = x - 6
comparing,
→ p + 3 = 1
→ p = 1 - 3 = (-2) (Ans.)
and,
→ q = 6 (Ans.)
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