Question

where does the graph of linear equation ax+by+c=0,a≠0,b≠0 cut x-axis

Answer 1

At X-axis coordinates of y=0,
Putting y=0,we get x=-c/a
Hence ,it cut x-axis at(-c/a,0)

Answer 2

The graph of linear equation ax+by+c=0,a≠0,b≠0 cut x-axis at point ( (-c/a),0) .

• At x-axis , the y coordinate become zero (0) .
• According to the question ,

       given equation of line is ax+by+c=0

       at x-axis , y coordinate = 0

       putting the value of y into the equation of line,

       ax + b(0) + c =0

        x = (-c / a)