where the object is placed in order to obtain a magnification of - 0.6 with a concave mirror
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m= -v/u
m = -6 =-v/u
6u = u
1/6u+1/u=1/f
1+6/6u=1/f
7f/6 = u
m = -6 =-v/u
6u = u
1/6u+1/u=1/f
1+6/6u=1/f
7f/6 = u
Answered by
11
Answer:
To obtain a magnification of -0.6 with a concave mirror, the object should be placed beyond the centre of curvature (that is 0.3).
Explanation:
- In a 'concave mirror', the magnification is the ratio of the "height of the object" or "image distance" to the "height of the object" or "object distance”.
Magnification (M) = image distance (v) /object distance (u)
- As per the Cartesian sign convention, the distance from the mirror to object is negative and from mirror to opposite side is positive.
- So when the object is placed "beyond the centre of curvature", the given magnification can be obtained.
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