where was jhon dalton born ? in which country? and at what age he became teacher and a principal ?
Answers
Answer:
Early Life. Dalton (1766–1844) was born into a modest Quaker family in Cumberland, England, and for most of his life—beginning in his village school at the age of 12—earned his living as a teacher and public
Explanation:
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Present Ages of Ram and Sham are in the ratio 2:3 .
After 5 years the ratio of their ages will be 3:4 .
To Find :
Present Age of Ram and Sham .
Solution :
\longmapsto\tt{Let\:Age\:of\:Ram\:be=2x}⟼LetAgeofRambe=2x
\longmapsto\tt{Let\:Age\:of\:Sham\:be=3x}⟼LetAgeofShambe=3x
After 5 years :
\longmapsto\tt{Age\:of\:Ram=2x+5}⟼AgeofRam=2x+5
\longmapsto\tt{Age\:of\:Sham=3x+5}⟼AgeofSham=3x+5
A.T.Q :
\longmapsto\tt{\dfrac{2x+5}{3x+5}=\dfrac{3}{4}}⟼
3x+5
2x+5
=
4
3
\longmapsto\tt{4(2x+5)=3(3x+5)}⟼4(2x+5)=3(3x+5)
\longmapsto\tt{8x+20=9x+15}⟼8x+20=9x+15
\longmapsto\tt{8x-9x=15-20}⟼8x−9x=15−20
\longmapsto\tt{-x=-5}⟼−x=−5
\longmapsto\tt\bf{x=5}⟼x=5
Value of x is 5 .
Therefore :
\longmapsto\tt{Present\:Age\:of\:Ram=2(5)}⟼PresentAgeofRam=2(5)
\longmapsto\tt\bf{10\:yrs}⟼10yrs
\longmapsto\tt{Present\:Age\:of\:Sham=3(5)}⟼PresentAgeofSham=3(5)