Math, asked by ekthameg, 1 year ago

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Answered by Anonymous
1
when x= 0-h
lim h->0 |0-h| cos 1/(0-h) = h cos -1/h = h cos 1/h= 0× [ -1,1] = 0

when x = 0+h
lim h->0 |0+h| cos 1/0+h = h cos 1/h = 0 × ([-1,1]= 0

which is equal to f(0) = 0

SO IT IS CONTINUOUS

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