Question

Which are the zero of p(x)=x2-2x,-8:

Answer 1

Answer:

-2 and +4

Step-by-step explanation:

p(x) = x² -2x - 8

∴x²-2x-8=0

x² -4x + 2x - 8 = 0

x(x-4) + 2(x-4) = 0

(x + 2)(x- 4)=0

Therefore,

x = -2 or +4