Math, asked by Kdjdjsjs, 11 months ago

Which are the zeroes of p(x) = x^2 -1

Answers

Answered by shraddha8429
5

Step-by-step explanation:

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Answered by harshpurwar83
0

Step-by-step explanation:

p(x) = x^2 -1

x^2-1=0

x^2=0+1

x^2=1

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