which are the zeros of p(x)=(x-1)(x-2)
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Answer:
p(x) = 0
p(x) = (x-1)(x-2)
(x-1)(x-2) = 0
so either,
(x-1) = 0; x = 1;
or,
(x-2) = 0; x = 2
thus, the zeroes are 1 and 2
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