Question

Which complex number is equivalent to
3 - 5i / 8+2i (i = √-1)
...... plz explain

Answer 1

Answer:

$\frac{3 - 5i}{8 + 2i} \\ \\ \frac{3 - 5 \times \sqrt{ - 1} }{8 + 2 \times \sqrt{ - 1} } \\ \\ \frac{3 - 5 \times - 1}{8 + 2 \times - 1} \\ \\ \frac{3 +. 5}{8 - 2} \\ \\ \frac{8}{6} \\ \\ \frac{4}{3} .answer$

hope it help you

Step-by-step explanation:

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