Question

Which constant must be added and subtracted to solve the quadratic equation 9x^2+3/4x-√2=0

by the method of completing the square? can someone give explanation plz it's very important...​

Answer 1

Answer:

${9x}^{2} + \frac{3}{4} x + \sqrt{2} = 0 \\ {9x}^{2} + \frac{3}{4} x = - \sqrt{2}$

New Constant = (1/2 * Coefficient of x)^2

${( \frac{1}{2} \times \frac{3}{4} )}^{2} \\ { (\frac{3}{8} )}^{2} \\ \frac{9}{64}$

So

$\frac{9}{64}$

should be added