Question

which contains more molecule 10 gram of Sulphur dioxide or
10 gram of oxygen

Answer 1

hey mate

here is ur answer

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Answer 2

10 grams of oxygen contains more molecules.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) $\text{Number of moles of sulphur dioxide}=\frac{10g}{64g/mol}=0.156moles$

1 mole of sulphur dioxide  contains=$6.022\times 10^{23}$ molecules

Thus 0.156 moles of sulphur dioxide contains=$\frac{6.022\times 10^{23}}{1}\times 0.156= 0.939\times 10^{23}$ molecules

b) $\text{Number of moles of oxygen}=\frac{10g}{32g/mol}=0.312moles$

1 mole of oxygen contains=$6.022\times 10^{23}$ molecules

Thus 0.312 moles of oxygen contains=$\frac{6.022\times 10^{23}}{1}\times 0.312=1.88\times 10^{23}$ molecules

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