Which does not use sp^3 hybrid orbitals in its bonding (A) H2O+ (B) BF3 (C) NH4+ (D) CH4
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Answered by
3
Answer:
B) BF3 as B uses sp² hybrid orbitals to form it. Others are sp³ hybridized.
B
/ | \ (1 s orbital and 2 p orbital as it's
F F F covalency is 3)
hope this will help you
Answered by
2
Answer:
B) BF3
Because,
B uses sp^2 hybrid orbitals
to form bond with Fluorine
as their is one lone pair
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