Which equation is the inverse of (x-4)^2-2/3=6y-12
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Thank you for asking this question. Here is your answer:
6y - 12 = (x-4)² - 2/3
6y - 12 = x² - 8x + 46/3
6y = x² - 8x + 82/3
Now we will divide each term by 6.
y = x²/6 - 4x/3 + 41/9
x = y²/6 - 4y/3 + 41/9
now we will solve this for y.
12 + √6(-17+9x)/3 , 12- √6(-17+9x)/3
f^-1(x)
f^-1(x) = 12+√6(-17+9x)/3 , 12 -√6(-17+9x)/3
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