Physics, asked by chennavani8964, 9 months ago

Which formula does not show ampere circuital law

Answers

Answered by Anonymous07
2

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Answered by vaibhavsemwal
0

Answer:

  • \int {B.}dl=\mu_0I
  • \triangledown \times H = \frac{\partial D}{\partial t} + J
  • \oint H.dl=I_{enc}

Any other formula than these three formula does not show ampere circuital law.

Explanation:

Ampere's circuital law can be stated as, “the line integral of the magnetic field surrounding closed-loop proportional to the sum of electric currents passing through that loop.”

Formula of ampere's circuital law:

\int {B.}dl=\mu_0I ----(1)

where,

B is the magnetic field,

I is the current through the loop,

\mu_0 is the magnetic permeability of free space.

Other forms of ampere's circuital law:

Maxwell's relation gives :  \triangledown \times H = \frac{\partial D}{\partial t} + J ----(1)

H is the magnetic field strength,

D is the displacement current,

J is the current density.

Also,

Integral form Maxwell's relation:

\oint H.dl=I_{enc}  -----(3)

Any other formula than (1), (2), and (3) does not show ampere circuital law.

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