which formula to use for eye defect correction problems class 10 cbse ?
adityamanthri:
my teacher gave this: f= -x
-x is for wt?
far point
of myopic eye
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I use for myopia the lens frmula
Where f is given may be or not it depends u is infinity and image is given in ques just siply apply the frmula 1/v-1/u=1/f
Where u is infinity
Where f is given may be or not it depends u is infinity and image is given in ques just siply apply the frmula 1/v-1/u=1/f
Where u is infinity
for hypermetropia ?
For hpermetropia u will be 25cm
why will i be 25 cm ?
Look our eye can only look till 25cm ao for hypermetropic person image is on his farpoint which mens his v but the object is in its final position which is 25 cm so the object is means u =25cm
For more clearnc study this topic throughly
ok
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