Math, asked by coolbroaa8781, 1 year ago

Which function has real zeros at x = 3 and x = 7?
A.f(x) = x2 + 4x – 21
B.f(x) = x2 – 4x – 21
C.f(x) = x2 – 10x + 21
D.f(x) = x2 – 10x – 21

Answers

Answered by farhanfayazali
5
A is the correct answer.....


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Answered by Anonymous
2

Answer:

option C .. x^2 - 10x +21

Step-by-step explanation:

f(x) = x^2 - 10x +21

x = 3 & 7

f(3) = (3)^2 -10(3) + 21

=. 9 - 30 +21

f(x) = 0

&

f(7) = (7)^2 -10(7) +21

= 49 -70 +21

f(7) = 0

hope it's helpful

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