Physics, asked by lavanya1614, 1 year ago

which has a angular velocity maximum hour or second hand

Answers

Answered by ctmganesan
0

The angular velocity is independent of the clock size, however for larger clocks the linear velocity of the pointers at the end of the hands will be greater.

The second hand goes through 2π radians in 1 min, or 2π radian/60 seconds,

so ω = π/30 rad.s-1 = 0.03 rad.s-1.

The minute takes one hour = 60 s/min × 60 min = 3600 s to go around,

so ω = 2π / 3600 rad.s-1 = 1.7 × 10-3 rad.s-1.

The hour hand takes 12 hours = 12 hours × 60 min/hour × 60 s/min = 43200 s to do 2π radians,

so ω = 2π rad/43200 s = 1.5 × 10-4 rad.s-1.

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Kumar Saurav

Kumar Saurav, May the dp/dt be with you.

Answered Mar 14, 2017 · Upvoted by Muthusamy P, M.Sc. Retired as Head of Department of Physics. Government of Tamilnadu, lndia. · Author has 511 answers and 513.6k answer views

The hour hand of the clock does not actually have a uniform instantaneous angular velocity but we can find its average angular velocity.

In a time period of 12 hours the hour hand moves an entire revolution.

ω=ΔθΔt

ω=2π rad12⋅60⋅60 s

ω=π21600 rad s−1

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Pranay Raj

Pranay Raj, former Student at AEES

Answered Sep 13, 2017

The minute takes one hour = 60 s/min × 60 min = 3600 s to go around, so ω = 2π / 3600 rad.s-1 = 1.7 × 10-3 rad.s-1. The hour hand takes 12 hours = 12 hours × 60 min/hour × 60 s/min = 43200 s to do 2π radians, so ω = 2π rad/43200 s = 1.5 × 10-4 rad.s-1. What is the angular velocity of the second hand?

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Amar Doshi

Amar Doshi, I experience Physics every day.

Answered Oct 14, 2017 · Author has 1k answers and 469.8k answer views

ω=ΔθΔt=2π12=π6 rad/h

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To view the LATEX source click '⋯' → Suggest Edits

LATEX composed at Formula Sheet

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Pranoy Biswas

Pranoy Biswas, Teacher at Don Bosco Junior College (2017-present)

Answered Mar 2, 2018

Angular velocity equals angular displacement devided by time elapsed .. So for hour hand of a clock to rotate 360° or 2π radian it takes total 12 hours or (12*60) minutes or( 12*60*60) seconds.

Therefore angular velocity = 2π/ (12*60*60) radian per second

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Nishith S Shetty

the angular velocity can be found by using the time period

the hour hand travels in a circle twice in a day

therefore angular displacement for one revolution in 12 hours=2pi.

time period is 12 hours or 12*60*60=144*600=43200 s.

ang vel =ang displacement /time period.

ang vel=2pi/43200 rad/s

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