Question

Which is a possible value of sinx a) 1.2 b) -2 c)1/6 d) √2​

Answer 1

Step-by-step explanation:

Correct option is

B

sin

−1

(0.96)

Let y=2sin

−1

0.8

Take sine both sides,

⇒siny=sin(2sin

−1

0.8)=2sin(sin

−1

0.8)cos(sin

−1

0.8)

[∵sin2θ=2sinθcosθ]

⇒siny=2(0.8)cos(cos

−1

1−(0.8)

2

)

⇒siny=1.6cos(cos

−1

0.6)=1.6(0.6)=0.96

∴y=sin

−1

(0.96)

Note: sin(sin

−1

x)=x if −

2

π

≤x≤

2

π

$Correct option is</p><p></p><p>B</p><p></p><p>sin−1(0.96)</p><p></p><p>Let y=2sin−10.8</p><p></p><p>Take sine both sides,</p><p></p><p>⇒siny=sin(2sin−10.8)=2sin(sin−10.8)cos(sin−10.8)</p><p></p><p>[∵sin2θ=2sinθcosθ]</p><p></p><p>⇒siny=2(0.8)cos(cos−11−(0.8)2)</p><p></p><p>⇒siny=1.6cos(cos−10.6)=1.6(0.6)=0.96</p><p></p><p>∴y=sin−1(0.96)</p><p></p><p></p><p>Note:  sin(sin−1x)=x if −2π≤x≤2π</p><p></p><p>$

Answer 2

Answer:

Here is your answer answer buddy,,,

Step-by-step explanation:

We know that the range is sin is

$- 1 \leqslant \sin(x) \leqslant 1$

A) 1.2 is not in between - 1 and 1

B)-2 is not in between - 1 and 1

C) So possible value is 1/6 as it lies in between - 1 and 1

D) root 2 = 1.4

Not between - 1 and 1

Answer is C

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