Question

which is a zero of the polynomial P(x)=x^3+x-3-3x^2;0,1,2,3

Answer 1

Firstly we have to rearrange the question...
p(x)=x3-3x2+x-3
now , when x=0
p(0)=(0)3-3(0)2+(0)-3
=-3
when x=1
p(1)=(1)3-3(1)2+1-3
= 1-3+1-3
=-4
when x=2
p(2)=(2)3-3(2)2+2-3
=8-12+2-3
=-5
when x=3
p(3)= (3)3-3(3)2+3-3
=27-27+3-3
=0
here is your answer