Question

Which is/are correct
-AH°
(A) 2.303 log K
+
RT
R
(B) AG° = – 2.303 RT log K
-AH"
(C) -2.303 log K
+
45°
RT2
R
(D) 2.303 log K
(AH° + AS)
RT​

Answer 1

Answer:

B) ∆G°= –2.303RT*logk –∆H°