Question

Which is/are correct statements about 1.7 gm of NH3 (A) It contain 0.3 mol H – atom (B) it contain 2.408  1023 atoms
(C) Mass % of hydrogen is 17.65% (D) vapour density of NH3
is 17

Answer 1

Answer:

From the question we get that the 1.7g of the NH3 will give 17/1.7 molecules of the NH3 atoms thus the number of the atoms present in the NH3 will be 4*6.023*10^23/10 which will be 2.408*10^23 atoms of the NH3.

Now the mass percentage of the hydrogen atoms can be calculated by using the formulae:-

Mass percentage = number of atoms*gram atomic mass*100/molar mass.

Here the number of hydrogen atom is 3 and the atomic mass is 1 and the molar mass is 17 so, on putting all these in the equation we will get the value of mass% as 300/17 = 17.65%.