Question

) Which is cheaper ?
40% HCl at the rate of Rs 6 per kg or 80% H,SO, at
the rate of Rs 2.5 per kg required to neutralise
7 kg of KOH.​

Answer 1

Answer:

neutralization of k0H by hcl

Explanation:

When neutralizing, you only care about hydrogen ions, not the entire chemical. So, with the HCl (lower case "L"), if you buy Rs.6 worth, you only get 400 grams of HCl which is 11 moles of HCl which is 11 moles of hydrogen ions. So, the price is Rs. 0.65 / mol

For the H2SO4, each molecule gives you 2 hydrogen ions. So, if you buy 2.5 Rs. worth, you get 800 grams of H2SO4 which is 8.16 moles of H2SO4 or 16.32 moles of hydrogen ions. So, Rs.2.5/16.32 moles = Rs. 0.15/mol.

So, the H2SO4 is 4-5 times cheaper per mol of hydrogen ions.