Math, asked by dhruvsalunkhe, 1 year ago

which is greater 2by7 of 3by4 or 3by5 of 5by8.compare the 2 make the denominater same and tell me which is greater between a and b plz answer with whole explanation

Answers

Answered by sappo786
4
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Answered by TooFree
6

 \textbf {Hey there, here is the solution.}

.............................................................................................

The fractions are:

 \bigg( \dfrac{2}{7}  \times\dfrac{3}{4} \bigg) \quad or \quad  \bigg( \dfrac{3}{5}  \times\dfrac{5}{8} \bigg)

.

Multiply the fractions:

 \bigg( \dfrac{6}{28} \bigg) \quad or \quad  \bigg( \dfrac{15}{40} \bigg)

.

Simplify:

 \bigg( \dfrac{6\div 2}{28 \div 2} \bigg) \quad or \quad  \bigg( \dfrac{15\div 5}{40 \div 5} \bigg)

 \bigg( \dfrac{3}{14} \bigg) \quad or \quad  \bigg( \dfrac{3}{8} \bigg)

.

Make the denominator the same:

 \bigg( \dfrac{3\times 4 }{14 \times 4} \bigg) \quad or \quad  \bigg( \dfrac{3\times 7}{8\times 7} \bigg)

 \bigg( \dfrac{12 }{56} \bigg) \quad or \quad  \bigg( \dfrac{21}{56} \bigg)

.

Compare:

 \bigg( \dfrac{12 }{56} \bigg) \quad < \quad  \bigg( \dfrac{21}{56} \bigg)

.

Conclusion:

 \bigg( \dfrac{3}{5}  \times\dfrac{5}{8} \bigg) \text{ is greater.}

.............................................................................................

 \textbf {Cheers }



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