Math, asked by iqbalmanhas15, 20 days ago

which is greater 3+2-5+11/-23+5-9 ​

Answers

Answered by aryanchouksey957
1

Answer:

3+2-5+11/-23+5-9

3+2-5+11= 11

-23+5-9= -27

hence 11> -27

Answered by sheeb12ansari
1

Given: 3+2-5+11\ or\ -23+5-9

We have to find the greater equation from the above expression.

By using the Bodmas rule, we are solving the above equation.

As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}

We are solving in the following way:

We have,

3+2-5+11\ or\ -23+5-9

Now,

a) \ 3+2-5+11\\=5-16\\=11

b)\ -23+5-9\\=-18-9\\=-27

After solving the above equation, we can say that 11is greater.

So, 3+2-5+11is the greater equation.

Hence, 3+2-5+11is the greater equation.

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