Which is the highest number that will divide 63,35,77 leaving 7 as remainder in each case?
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HCF(63, 35, 77) = 7
In order to leave a Remainder “7”, we need to divide 63, 35 & 77 by 14 (HCF(63, 35, 77) + Remainder).
In order to leave a Remainder “7”, we need to divide 63, 35 & 77 by 14 (HCF(63, 35, 77) + Remainder).
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