Question

which is the probability that a non leap year should have 53 Sunday

Answer 1

hii mate!!!!!!!

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For solving this question we should know a basic fact about a year i.e. it has 52 weeks.

52 weeks means 52×7 = 364 days.

If the year in an ordinary year, the one odd day could be Monday,Tuesday, Wednesday…… Sunday. Thus the probability of getting a sunday is 1/7.

If the year is a leap year, the two odd days could be

Mon Tue, Tue Wed, Wed Thu , Thu Fri , Fri Sat , Sat Sun , Sun Mon.

Thus the probability of getting a sunday is 2/7
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Hope this Helps !!

@Noor!!!!!!!!!!

Answer 2

here in ques it is not specifically said that the year is leap year or non leap year . so i am writing the answer for both conditions.

considering a non leap year

see we have 365 days in a non-leap year.

52 weeks and one extra day= 365 days

52 weeks means definitely there are 52 sundays (this is true for all other days also).

that means if the extra day comes out to be sunday then we will have 53 sundays.

so now the ques boils down to what is the prob of this extra day to be a sunday .

this extra one day can be {monday or tuesday or wednesday or thursday or friday or saturday or sunday }= samplespace (s)

i.e n(s) = 7

so prob of this extra one day to be a sunday is 1/7.

[note - this is also the answer for having 53 mondays or 53 tuesdays or 53 wednesdays or 53 thursdays or 53 fridays or 53 saturdays.]

considering a leap year

leap year contains 366 days

52 weeks plus two two extra days

52 weeks means definitely there are 52 sundays (this is true for all other days also).

if either of these two is sunday then we will have 53 sundays

these two days can be {mon, tue} or { tue , wed} or { wed , thurs} or {thurs , fri} or { fri, sat} or { sat , sun} or {sun , mon} i.e total =7

out of these only two outcomes i.e { sat , sun} and {sun , mon} is having sunday with them .

so our desired prob is 2/7.