which is the smallest five digit number exactly divisible by 85
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Answered by
3
Hey buddy
your answer is
17
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Answered by
8
Answer:
Dividend = divisor × quotient + remainder
Dividend = 10000* Divisor = 85
10000 = 85 × 117 + 55
To find required number we have
add number = divisor - remainder. = 85 - 55
= 30 to 10000
Therefore,
Smallest 5 digit number exactly divisible by 85 is 10030.
Verification:
10030 = 85 × 118 + 0
Thanks
rampalsaket123456:
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