Question

Which is the smallest number of five digits which is divided by 41?

Answer 1

10004 is the smallest five digits number which is divided by 41

Answer 2

Answer: 10004

Step-by-step explanation:  

We know that smallest 2 digit number is 10.

Smallest three digit number is 100.

Similarly smallest five digit number is 10000.

Here we use,

Division algorithm:

Dividend = divisor × quotient + remainder

Dividend = 10000

Divisor = 41

10000 = 41 × 243 + 37

To find required number we have

add number = divisor - remainder

                      = 41 - 37

                      = 4 to 10000

Therefore, Smallest number of five digits which is divided by 41 is 10004.

Verification:

10004 = 41 × 244 + 0