Which law of chemical combination is illustrated by the fact that 168 g Fe reacts with 72 g H2O to from 232g Fe3 O4 and 8g H2 ?
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At reactant side molar mass of Fe and H2O= 168+72=240g.m
At product side molar mass of Fe3O4 and H2= 232+8=240g.m
As mass constant so it is obeying
"LAW OF CONSERVATION OF MASS"
At product side molar mass of Fe3O4 and H2= 232+8=240g.m
As mass constant so it is obeying
"LAW OF CONSERVATION OF MASS"
Answered by
1
In this case
168g + 72 g = 240 g LHS Reactants
232g + 8g = 240 g RHS Products
law of conservation of mass
168g + 72 g = 240 g LHS Reactants
232g + 8g = 240 g RHS Products
law of conservation of mass
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