Question

Which linear equation can be derived from this proportion?x-9/x-3 = 2/5 A. 2x − 9 = 5x − 3 B. 2x − 3 = 5x − 9 C. 2x − 6 = 5x − 45 D. 2x − 18 = 5x − 15

Answer 1

Answer:

Required linear equation is 5x-45 = 2x-6

So, option C is the correct answer.

Step-by-step explanation:

Given,

$\frac{x - 9}{x - 3} = \frac{2}{5}$

By cross multiplication,

$5 \times (x - 9) = 2 \times (x - 3) \\ 5x - 45 = 2x - 6$

Therefore, option C is the correct answer.

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

#SPJ2

Answer 2

Answer:

Step-by-step explanation: