which number must be divided by 9408 to get perfect square
Answers
To find the smallest number by which 9408 must be divided so that the quotient is a perfect square, we have to find the prime factors of 9408.
9408 = 2*2*2*2*2*2*3*7*7
Prime factors of 9408 are 2, 2, 2, 2, 2, 2. 3, 7, 7
Out of the prime factors of 9408, only 3 is without pair.
So, 3 is the number by which 9408 must be divided to make the quotient a perfect square.
9408/3 = 3136
Square root of 3136
56
_____________
5 | 3136
5 | 25
___ |______
106 | 636
6 | 636
|_______
| 000
So, √3136 = 56
Answer:)
To find the smallest number by which 9408 must be divided so that the quotient is a perfect square, we have to find the prime factors of 9408.
9408 = 2*2*2*2*2*2*3*7*7
Prime factors of 9408 are 2, 2, 2, 2, 2, 2. 3, 7, 7
Out of the prime factors of 9408, only 3 is without pair.
So, 3 is the number by which 9408 must be divided to make the quotient a perfect square.
9408/3 = 3136
Square root of 3136
56
_____________
5 | 3136
5 | 25
___ |______
106 | 636
6 | 636
|_______
| 000
So, √3136 = 56