Question

which of following has highest boiling point .
a 0.01 m glucose
b 0.01m k2SO4
c 0.01 MKNO3
d 0.01 urea​

Answer 1

Answer:

C) 0.01 MKNO3

Explanation:

Electrolytes -

Solute which dissociates / associates when dissolved in solvent are known as Electrolytes

- wherein

e.g. NaCl2, CaCl2, KCl

Elevation in boiling point is a colligative property which depends upon the number of solute particles. Greater the number of solute particle in a solution higher the extent of elevation in boiling point.

Answer 2

0.01 m $K_2SO_4$ will have highest boiling point.

Explanation:

Elevation in boiling point

$\Delta T_b=i\times k_b\times m$

where,

$\Delta T_b$ = elevation in boiling point

$k_b$ = boiling point constant

m = molality

i = Van't Hoff factor

a) 0.01 m glucose

, i= 1 as it is a non electrolyte and does not dissociate.

b) For 0.01 m $K_2SO_4$

$K_2SO_4\rightarrow 2K^+SO_4^-$

, i= 3, as it is a electrolyte and dissociate to give 3 ions and concentration will be $2\times (0.01)+0.01=0.03m$

c) For 0.01 m $KNO_3$

$KNO_3\rightarrow K^+NO_3^-$

, i= 2 , as it is a electrolyte and dissociate to give 2 ions and concentration will be $(0.01+0.01)=0.02m$

d) 0.01 m urea

, i= 1 as it is a non electrolyte and does not dissociate

As the concentration is highest for 0.01 m $K_2SO_4$ , it will have highest boiling point.

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