Question

Which of following solution has highest boiling point a) 0.01m glucose
b) 0.01m K2SO4
C) 0.01 MKNO3
d) 0.01m urea

Answer 1

Answer:

d has highest boiling point

Answer 2

0.01 m $K_2SO_4$ has highest boiling point

Explanation:

The expression of elevation in boiling point is given as:

$\Delta T_b=i\times k_b\times m$

where,

$\Delta T_b$ = Elevation in boiling point

i = Van't Hoff factor  

$T_b$ = change in boiling point

$k_b$ = boiling point constant

m = molality

a)  0.01 m glucose

Value of i =1 as it is a non electrolyte

b)  0.01 m $K_2SO_4$

$K_2SO_4\rightarrow 2K^++SO_4^{2-}$

Value of i = 3

c) 0.01 m $KNO_3$

$KNO_3\rightarrow 2K^++NO_3^{-}$

Value of i = 2

d) 0.01 m urea

Value of i = 1 as it is a non electrolyte

Thus as 0.01 m $K_2SO_4$ has highest value of i. the elevation in boiling point will be maximum.

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