Which of the folllowing is an acceptable set
of qunatum numbers
(in the order n, l, m,, m)
(TSM(III)-2016
1) 2, 1, 0, 0 2) 2, 2, 0, 1/2
3) 2, 0, 2, + 1/2 4) 2, 1, -1, 1/2
Answers
Answer:
Select the correct statement(s) among the following:
(i) Total number of orbitals in a shell with principal quantum number 'n' is n
2
.
(ii) Total number of subshell in the nth energy level is n.
(iii) The maximum number of electrons in a subshell is given by the expression (4l+2).
(iv) m=l+2, where l and m are azimuthal and magnetic quantum numbers
Explanation:
ANSWER
The statements (i), (ii) and (iii) are correct.
(i) Total number of orbitals in a shell with principal quantum number 'n' is n
2
.
Thus, for n=1, the number of orbitals =1
2
=1. It includes 1s orbital.
For n=2, the number of orbitals =2
2
=4. It includes 2s, 2p
x
, 2p
y
and 2p
z
orbitals.
For n=3, the number of orbitals =3
2
=9. It includes 3s, 3p
x
, 3p
y
, 3p
z
d
xy
,d
xz
,d
yz
, d
x
2
−y
2
and d
Z
2
orbitals.
(ii) Total number of subshell in the nth energy level is n
Thus, for n=1, only 1 subshell is present. It includes s orbital.
For n=2, two subshells are present. It includes s and p orbitals.
For n=3, three subshells are present. It includes s, p and d orbitals.
(iii) The maximum number of electrons in a subshell is given by the expression (4l+2)
Thus, s subshell with l=0 has (4l+2)=(4(0)+2)=2 electrons.
p subshell with l=1 has (4l+2)=(4(1)+2)=6 electrons.
d subshell with l=2 has (4l+2)=(4(2)+2)=10 electrons.
f subshell with l=3 has (4l+2)=(4(3)+2)=14 electrons.
(iv) m=−l,....−1,0,+1,.....+l, So m=2l+1 where l and m are azimuthal and magnetic quantum numbers
Thus when l=3
m=−3,−2,−1,0,+1,+2,+3
Thus, there are 7 values of m. 2l+1=2(3)+1=7
I have taken different similar question so that you do it by yourself.
plz mark as brainliest .
hope it helps
question is above.
thx.
...
...