Question

 Which of the following 0.1 M complex compound solutions will have the minimum electrical conductivity?​

Answer 1

Question - Which of the following 0.1M complex compound solutions will have the minimum electrical conductivity?

(a) Hexammine platinum (IV) chloirde

(b) Chloropentammine platinum (IV) chloirde

(c) Dichlorotetrammine platinum (IV) chloirde

(d) Trichlorotriammine platinum (IV)chloirde

Answer - Minimum electrical conductivity will be given by (d) Trichlorotriammine platinum (IV)chloirde.

The given compounds have formula -

• Hexammine platinum (IV) chloirde

[Pt(NH3)6] Cl4

• Chloropentammine platinum (IV) chloirde

[Pt(NH3)5Cl] Cl3

• Dichlorotetrammine platinum (IV) chloirde

[Pt(NH3)4Cl2] Cl2

• Trichlorotriammine platinum (IV)chloirde

[Pt(NH3)3Cl3] Cl

In the compound Hexammine platinum (IV) chloirde, ions formed will be 4 negative and 1 positive ion. Thus, total number of ions will be 5.

In the compound Chloropentammine platinum (IV) chloirde, 3 negative ions and 1 positive ion will be released. Thus, total 4 ions will be present.

In the compound Dichlorotetrammine platinum (IV) chloirde, 2 negative ions and 1 positive ion will be released. Thus, total number of ions released will be 3.

In the compound Trichlorotriammine platinum (IV)chloirde, one negative and one positive ion will be released. Thus, 2 ions will be in the solution.

Since solutions are equimolar and conduction of electricity depends on numbe of ions, the compound Trichlorotriammine platinum (IV)chloirde will show minimum electrical conductivity.