which of the following cannot form
minimum boiling azeotrope in
a . n-heptane and n-hexane
b.Acetone and auiline.
Both a and b
6 chcl3
Answers
Answer:
Acetone and aniline cant show min boiling azeotrope as they show negative deviation.
The correct option is option b) Acetone and aniline.
Explanation:
Azeotropes are a kind of liquid mixture whose composition and boiling point are preserved after distillation. Raoult's law states that a mixture that deviates positively from it will produce minimal boiling azeotropes, whereas a mixture that deviates negatively will produce maximum boiling azeotropes.
The vapor pressure increases for minimal boiling azeotropes whereas it decreases for maximum boiling azeotropes. Azeotropes are referred to as minimum boiling azeotropes when their boiling point is lower than the boiling point of the molecules that make up the azeotrope.
In these azeotropes, the interactions between the molecules of the solvent and the solute are weaker than those between the molecules of the solvent and the solute, and as a result, their boiling point is lower.
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