Question

Which of the following combination of volumes of C2 H4 and O2 respectively is required to obtain 400 ml of co2
a)100,300
b)200,600
c)200,200
d)300,300

Answer 1

Go through the attachment :)

Answer 2

Answer:

200,600

Explanation:

Given:

The volume of $C_2H_4$ and $O_2$ is 400ml

To find:

Combination of volume

Solution:

The pressure of a sample of gas inside a fixed, rigid container also rises as its temperature rises. This results from the fact that a rise in temperature raises the gas's kinetic energy. As a result, the gas molecules exert more force when they collide with the container's wall, increasing pressure.

We may directly relate the cooling of a gas and pressure using a graph of pressure vs temperature. The pressure is reduced until a liquid is formed when a gas is cooled at a constant volume.

$C_2H_43O_2 - > 2CO_2+2H_2O$

Now applying Gay- Lussac's law

$C_2H_4+3O_2- > 2CO_2+2H_2O$

Thus the ratio of $C_2H_4$ and $O_2$ IS 1:3:2

Volume obtained for 2 moles of $CO_2$ = 400mL

1 mole of $CO_2$ = 200mL

According to the volume ratio

Volume of $O_2=2\times200=600mL$

Volume of $C_2H_4=1\times200=200mL$

Option B is the correct answer.

What is Gay lussac's Law?

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