Which of the following complexes would
show geometrical isomerism?
[CoCl2Br_]2 [PT(NH3)3Cl]+
[Pt en Cl2]
[Ni(CN)]2-
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Answer:
In [Ni(CN)4]2–, strong ligands i.e. CN- are present. These are able to pair the two unpaired electrons in the d oribital and thus no unpaired electrons will be left. The hybridization and shape of [Ni(CN)4]2- will be dsp2 and square planar respectively.8
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