Which of the following compounds give Vic diol with Na/c2h5oh.
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Explanation:
Step 1 - one electron transfer from sodium to carbonyl group:
Na⋅+RCH=O⟶Na++RCH⋅−O−
Step 2 - abstraction of a proton from ethanol:
CH3CH2OH+RCH⋅−O−↽−−⇀CH3CH2O−+RCH⋅−OH
This step is an equilibrium step, and is driven toward products by the second electron transfer (which consumes the RCH⋅−OH.
Step 3 - one electron transfer from a second sodium atom to the organic radical:
Na⋅+RCH⋅−OH⟶Na++RCH:−−OH
Step 4 - second proton transfer from ethanol:
CH3CH2OH+RCH:−−OH⟶CH3CH2O−+RCH2OH
This reaction, while technically an acid-base equilibrium, essentially goes to completion because of the vast disparity in acidity of C−H and O−H.
The net reaction is:
2Na+RCH=O+2CH3CH2OH⟶RCH2OH+2CH3CH2ONa
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