Which of the following contain least no. of molecules
a) 22gm CO2
b) 1.2 lit of CH4
c) 0.1 mole of H2O
d) 2.3gm of N2
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Answer:
Let N be the Avogadro's number.
Mass is divided with molar mass to obtain the number of moles.
The number of moles are multiplied with Avogadro's number to obtain number of molecules.
(A) 52 g of N
2
O
5
=
(28+80)g/mol
52g
×N=0.48N
(B) 36 g of H
2
O=
18g/mol
36g
×N=2N
(C) 28 g of CO =
28g/mol
28g
×N=N
(D) 51 g NH
3
=
17g/mol
51g
×N=3N
Hence, 52 g of N
2
O
5
contains least number of molecules.
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