Which of the following contains maximum number of atoms?
A. 18g of water
B. 16g of o2
C. 4.4g of co2
D. 16g of ch4
Answers
Explanation:
Given -
- 18g of H2O
- 16g of O2
- 4.4g of CO2
- 16g of CH4
To Find -
- Which of the following contains maximum number of atoms?
As we know that :-
- mass = n(mole) × GAM/GMM
- No. of molecules = n × Na
Now,
We have to check all compound to say which contains maximum number of atoms.
Option 1)
18g of H2O
Solution :-
GMM of H2O = 1×2 + 16 = 18 g/mol
mole of H2O = 18/18 = 1 mol
Now,
No. of molecules = 1 × 6.022 × 10²³
➳ 6.022 × 10²³ atoms are present in 18 g of H2O
Option 2)
16g of O2
Solution :-
GAM of O2 = 16×2 = 32 g/mol
mole of O2 = 16/32 = 1/2 mol
Now,
no. of molecules = 1/2 × 6.022 × 10²³
➳ 3.011 × 10²³ atoms are present in 16g of O2
Option 3)
4.4g of CO2
Solution :-
GMM of CO2 = 12 + 16×2 = 12 + 32 = 44 g/mol
mole of CO2 = 4.4/44 = 1/10 mol
Now,
no. of molecules = 1/10 × 6.022 × 10²³
➳ 6.022 × 10²² atoms are present in 4.4 g of CO2
Option 4)
16g of CH4
Solution :-
GMM of CH4 = 12 + 1×4 = 12 + 4 = 16 g/mol
mole of CH4 = 16/16 = 1 mol
Now,
no. of molecules = 1 × 6.022 × 10²³
➳ 6.022 × 10²³ atoms are present in 16g of CH4
Hence,
Both (18g of H2O and 16g of CH4) contains same no. of atoms.
Therefore,
Option I and Option IV (Both) are correct.
(More than one correct question)