Chemistry, asked by nareshramesh056, 8 months ago

Which of the following contains maximum number of atoms?
A. 18g of water
B. 16g of o2
C. 4.4g of co2
D. 16g of ch4

Answers

Answered by TrickYwriTer
56

Explanation:

Given -

  1. 18g of H2O
  2. 16g of O2
  3. 4.4g of CO2
  4. 16g of CH4

To Find -

  • Which of the following contains maximum number of atoms?

As we know that :-

  • mass = n(mole) × GAM/GMM
  • No. of molecules = n × Na

Now,

We have to check all compound to say which contains maximum number of atoms.

Option 1)

18g of H2O

Solution :-

GMM of H2O = 1×2 + 16 = 18 g/mol

mole of H2O = 18/18 = 1 mol

Now,

No. of molecules = 1 × 6.022 × 10²³

➳ 6.022 × 10²³ atoms are present in 18 g of H2O

Option 2)

16g of O2

Solution :-

GAM of O2 = 16×2 = 32 g/mol

mole of O2 = 16/32 = 1/2 mol

Now,

no. of molecules = 1/2 × 6.022 × 10²³

➳ 3.011 × 10²³ atoms are present in 16g of O2

Option 3)

4.4g of CO2

Solution :-

GMM of CO2 = 12 + 16×2 = 12 + 32 = 44 g/mol

mole of CO2 = 4.4/44 = 1/10 mol

Now,

no. of molecules = 1/10 × 6.022 × 10²³

➳ 6.022 × 10²² atoms are present in 4.4 g of CO2

Option 4)

16g of CH4

Solution :-

GMM of CH4 = 12 + 1×4 = 12 + 4 = 16 g/mol

mole of CH4 = 16/16 = 1 mol

Now,

no. of molecules = 1 × 6.022 × 10²³

➳ 6.022 × 10²³ atoms are present in 16g of CH4

Hence,

Both (18g of H2O and 16g of CH4) contains same no. of atoms.

Therefore,

Option I and Option IV (Both) are correct.

(More than one correct question)

Similar questions