Question

Which of the following electronic configurations is wrong?
(a) Be (3) = 2, 1 (b) O(8) = 2, 6
(c) S(16) = 2, 6, 8 (d) P(15) = 2, 8, 5

Answer 1

$\bf\large\underline\pink{Answer:-}$

d) (15) = 2,8,5

Answer 2

(c) S(16) = 2, 6, 8

Explanation:

Atomic configuration is written as 1s2 2s2 2p6 3s2 3p6 3d10....

Sulphur with atomic number 16 will have electronic configuration as 2, 8, 6.

The second shell can hold 8 electrons. Only after that is full, we can start filling the 3rd shell which will have the remaining 6 electrons.

Option C is the answer.