Question

Which of the following elements can show covalency greater than 4?
1. Be
2. S
3. P
4. Al


Help me with dis question it is multi correct option

Answer 1

Answer:

2. S and 3. P 4.Al can show covalency greater than 4.

Explanation:

These elements have empty d-orbitals which can be used to form bonds.Therefore,they can show covalency greater than 4.Let us understand it with the help of electronic configuration :-

Be

Electronic configuration :- $1s^2\:2s^22p^0$

• It can show covalancy of four as it has one s orbital and three p orbital.

S

Electronic configuration:- $1s^2\:2s^22p^6\:3s^23p^43d^0$

• It has vacant d orbital and thus,it can extend it's covalancy above 4.

P

Electronic configuration:- $1s^2\:2s^22p^6\:3s^23p^33d^0$

• It has also vacant d orbital and thus,it can extend it's covalancy above 4.

Al

Electronic configuration:- $1s^2\:2s^22p^6\:3s^23p^13d^0$

• It has also vacant d orbital and thus,it can extend it's covalancy above 4.