Question

Which of the following equations has x = 3 as a solution?

a. x+ 2 = 5
b. x- 2 = 0
c. 2x + 1 = 0
d. x + 4 = 6

Answer 1

Answer:

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

f(1) = 13 − 3×12 – 2×1 + 4 = 0 1 is a solution

f(−1) = (−1)3 − 3×(−1)2 – 2×(−1) + 4 = 2

f(2) = 23 − 3×22 – 2×2 + 4 = −4

f(−2) = (−2)3 − 3×(−2)2 – 2×(−2) + 4 = −12

f(4) = 43 − 3×42 – 2×4 + 4 = 12

f(−4) = (−4)3 − 3×(−4)2 – 2×(−4) + 4 = −100

The only integer solution is x = 1. When we have found one solution we don’t really need to test any other numbers because we can now solve the equation by dividing by (x − 1) and trying to solve the quadratic we get from the division.

Answer 2

Answer:

a

Step-by-step explanation:

a).

x+2=5

x=5-2

x=3

Hope u fine bro...❤❤