Question

which of the following form of Pythagorean triplet (a)6,8,10 (b) 12,25,37​

Answer 1

here is ur answer 》》 a) 6, 8,10
●●
$6 { }^{2} = 36$
$8 {}^{2} = 64$
$10 { }^{2} = 100$
■according to Pythagoras theorem
☆
$a {}^{2} + b {}^{2} = c {}^{2}$
$6 {}^{2} + 8 { }^{2} = 36 + 64 = 100 = 10 {}^{2}$
●therefore-_6,8,10 is a Pythagorean triplet

Answer 2

$\bold\red{\underline{\underline{Answer:}}}$

${(a)6,8,10 \ is \ pythagorean \ triplet.}$

$\bold\orange{Given:}$

$\bold{=>(a)6,8,10}$

$\bold{=>(b)12,25,37}$

$\bold\pink{To \ find:}$

$\bold{Pythagorean \ triplet}$

$\bold\green{\underline{\underline{Solution}}}$

$\bold{(a)}$

$\bold{10^{2}=100...(1)}$

$\bold{6^{2}+8^{2}=36+64=100...(2)}$

$\bold{From \ (1) \ and (2)}$

$\bold{10^{2}=6^{2}+8^{2}}$

$\bold\purple{\tt{\therefore{6,8,10 \ is \ pythagorean \ triplet.}}}$

_______________________________________

$\bold{(b)}$

$\bold{37^{2}=1369...(1)}$

$\bold{25^(2)+12^{2}=625+144=769...(2)}$

$\bold{From \ (1) \ and (2)}$

$\bold{35^{2} \ not \ equals \ to \ 25^{2}+12^{2}}$

$\bold\purple{\tt{\therefore{12,25,37 \ is \ not \ a \ pythagorean \ triplet. }}}$